# Projectile Motion with only the vertical/ horizontal height and angle given

## Main Question or Discussion Point

I need help! I understand regular projectile, but when it comes to using an angle it drives me crazy!
The vertical distance is 15.01 m
Horizontal distance is 21.84 m
Angle is 45°
I figured the time to be 2.1 sec
I need the velocity
And VsubF is 0...right?
I just need the help guys, thanks

Related Other Physics Topics News on Phys.org
Which quantities are given and which did you find out (and how)?
It would be nice to show the problem you are trying to solve.

I need help! I understand regular projectile, but when it comes to using an angle it drives me crazy!
The vertical distance is 15.01 m
Horizontal distance is 21.84 m
Angle is 45°
I figured the time to be 2.1 sec
I need the velocity
And VsubF is 0...right?
I just need the help guys, thanks
Don't worry about the angle. V and H motion are still independent. Break the trajectory in half, and let's check if your time is correct. A falling object falls as d=0.5gt^2, this one fell 15m, if G≈10m/s^2 then this one fell:
15m=0.5*9.8(m/s^2)*t^2 --> t=√15/4.9=1.7496s
Vhorizontal=Δx/t=21,84m/(2*1.7496s)=6.241m/s (the time is doubled because the time in the first step is only for the falling part of the motion.
Vinitialvertical=Vhorizontal
Vinitialtotal=Vhorizontal*√2 by Pythagoras.

If those aren't what you're looking for, you need to describe the problem more.