Projectile Motion with only the vertical/ horizontal height and angle given

In summary, the person is struggling with using an angle in projectile motion and needs help finding the velocity. They have determined the vertical and horizontal distance and time, and are unsure if VsubF is 0. They are advised to break the trajectory in half and check their calculated time. The conversation also mentions finding the initial velocity using Pythagoras' theorem. The person is asked to provide more details about the problem they are trying to solve.
  • #1
I need help! I understand regular projectile, but when it comes to using an angle it drives me crazy!
The vertical distance is 15.01 m
Horizontal distance is 21.84 m
Angle is 45°
I figured the time to be 2.1 sec
I need the velocity
And VsubF is 0...right?
I just need the help guys, thanks
 
Physics news on Phys.org
  • #2
Which quantities are given and which did you find out (and how)?
It would be nice to show the problem you are trying to solve.
 
  • #3
Otakuchica said:
I need help! I understand regular projectile, but when it comes to using an angle it drives me crazy!
The vertical distance is 15.01 m
Horizontal distance is 21.84 m
Angle is 45°
I figured the time to be 2.1 sec
I need the velocity
And VsubF is 0...right?
I just need the help guys, thanks

Don't worry about the angle. V and H motion are still independent. Break the trajectory in half, and let's check if your time is correct. A falling object falls as d=0.5gt^2, this one fell 15m, if G≈10m/s^2 then this one fell:
15m=0.5*9.8(m/s^2)*t^2 --> t=√15/4.9=1.7496s
Vhorizontal=Δx/t=21,84m/(2*1.7496s)=6.241m/s (the time is doubled because the time in the first step is only for the falling part of the motion.
Vinitialvertical=Vhorizontal
Vinitialtotal=Vhorizontal*√2 by Pythagoras.

If those aren't what you're looking for, you need to describe the problem more.
 

1. What is projectile motion?

Projectile motion refers to the motion of an object that is projected into the air and then moves under the influence of gravity. It is a combination of horizontal and vertical motion.

2. How is the angle of projection related to the range of a projectile?

The angle of projection is directly related to the range of a projectile. The range will be maximum when the angle of projection is 45 degrees.

3. Can you calculate the time of flight for a projectile with only the vertical/horizontal height and angle given?

Yes, the time of flight can be calculated using the formula t = (2 * vertical height / g), where g is the acceleration due to gravity (9.8 m/s²).

4. How can you find the final velocity of a projectile with only the vertical/horizontal height and angle given?

The final velocity of a projectile can be found using the formula v = sqrt(2 * g * vertical height), where g is the acceleration due to gravity (9.8 m/s²).

5. Can you find the maximum height of a projectile with only the vertical/horizontal height and angle given?

Yes, the maximum height of a projectile can be found using the formula h = (vertical height)^2 / (2 * g), where g is the acceleration due to gravity (9.8 m/s²).

Suggested for: Projectile Motion with only the vertical/ horizontal height and angle given

Replies
46
Views
2K
Replies
14
Views
943
Replies
2
Views
642
Replies
16
Views
1K
Replies
8
Views
700
Replies
8
Views
2K
Back
Top