A missile is launched from the ground making 45 degree with the horizontal to hit a target at a horizontal distance of 300 km. If it is required to hit a target at a horizontal distance of 675 km launched at same angle with horizontal, find the percentage change in its velocity of projection. (Answer is 50% increase)
The Attempt at a Solution
I did it like this but I got 44.5% whereas the answer is 50%
So I did it like this...
I put R= 300km and 675km in the given formula in two equations....
I got √100/3 and √75
Therefore to find % increase
√100/3 divided by √75 * 100
I got 44.5%
But the answer is 50%.....please help