Projectile Problems: Range, Time & Theta C (6 Sig Digits)

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The projectile problem involves calculating various parameters for a projectile launched at an initial velocity of 49 m/s at an angle of 76 degrees, neglecting air resistance. The range of the projectile is determined to be 115.020 meters, with a total flight time of 9.70295 seconds. The time at which the projectile is farthest from the launch point is calculated to be 5.55736 seconds, resulting in a maximum distance of 130.705 meters from the launch point. The critical angle, which determines when the projectile is always moving away from the launch point, is found to be approximately 71.4856 degrees. The discussion highlights the importance of using correct equations and understanding the relationship between height and distance in projectile motion.
  • #51
you just completely lost me...what are you using that site for? like what are you using for the quadratic? i never got that far (i dislike derivatives like crazy)
 
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  • #52
nm, I'm getting tired...i got it...thanks :)
 
  • #53
yeah I am not too fond of them either. I took this equation
(Vox*t)(Vox) + (Voy*t-.5*g*t^2)(Voy-g*t) = 0 divide both sides by t you get
Vox^2 + (Voy - .5*g*t)(Voy - g*t) = 0 you can create a quadratic with this
Vox^2 + Voy^2 - (.5*g*t*Voy) - (g*t*Voy) + (.5*g^2*t^2)
plug in g= 9.8; Vox= 11.8542; Voy= 47.5445 youll get a quadratic that you can plug into the site I linked
 
  • #54
(Vox^2 + Voy^2) - (14.7t*Voy) + (48.02t^2) = 0
2400.9998 - 698.904t + 48.02t^2 = 0
 
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