How Do You Calculate the Final Velocity of a Projectile?

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To calculate the final velocity of a projectile, the initial velocity, angle, and height must be considered. A rock is thrown from a 50m cliff with an initial velocity of 7m/s at a 53-degree angle. The equations used include vertical and horizontal components of motion, with gravity affecting the vertical component. The calculations led to confusion regarding the variable 'x,' which was used inconsistently. Ultimately, the expected final velocity before impact is 32 m/s, indicating a need for clarification in the calculations and understanding of the equations.
vinamas
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Homework Statement


A rock is thrown from a cliff that is 50m long with an initial velocity of 7m/s and an angle of 53, find the rock's veloctity before it hits the ground

Homework Equations


vfy=sin(theta)*vi-gt
vf^2=(vi*sin(theta))^2-2gy

The Attempt at a Solution


x=vi*cos()t
t=x/(vi*cos)
x=7*cos(53)-2*9.81*(x/(vi*cos(53)))^2
x =2.49 or x=-6.11
at this point i tried to plug in x into vf^2=(vicos)^2-2gy
but none of them give 32 m/s which is the answer according to the answer's sheet
 
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Some questions for you to consider:
In your solution what is x? It appears you are using x to represent two different quantities.
Why do you think the time of flight is given by your second equation?
 
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