Projecting a vector onto a plane

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SUMMARY

The discussion focuses on the mathematical process of projecting a vector onto a plane defined by the equation x + 3y + 2z = 0, specifically in the direction of the vector d = 2i + j - k. The initial approach involves defining a vector u in R^3 and determining the intersection with the plane using a parameter t. A correct method is suggested, which involves projecting the vector onto the normal vector of the plane and then adjusting for the specified direction, clarifying that the projection is not orthogonal.

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fishingspree2
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Homework Statement


Project a vector into the plane x + 3y + 2z = 0 in the direction d = 2i + j - k


The Attempt at a Solution


Let u = ai + bj +ck, a vector in R^3.
then u + t*d = (a+2t)i + (b+t)j + (c-t)k where t is a real number

when u + t*d hits the plane then

(a+2t) + 3(b+t) + 2(c-t) = 0
solve for t, substitute into u = t*d, then plug in the a,b,c values for the vector to be projected

Is this approach correct?

Thank you very much
 
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I presume that you mean "project the vector [itex]2\vec{i}+ \vec{j}+ \vec{k}[/tex] onto the plane x+ 3y+ 2z= 0. <br /> <br /> Use the fact that the vector [itex]\vec{i}+ 3\vec{j}+ 2\vec{z}[/tex] is perpendicular to the plane. Project the given vector onto that normal vector, then subtract that from the given vector.[/itex][/itex]
 
Hello,

No i meant project some vector on the plane in a direction parallel to 2i + j + k, which is not an orthogonal projection.
 

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