Projecting a Vector onto a Plane

[Niles]

Homework Statement

Hi

Say I have a vector v=(v_x, v_y, v_z) that makes an angle α with the x-axis. The amount of v projected onto the x-axis I find from the dot product

v.x = √(v_x² + v_y² + v_z²)cos(α)

I am also interested in finding the amount of v in the plane normal to the x-axis, i.e. I want to project v onto the y-z plane. Is this simply given by v.(y + z)?

 

[HallsofIvy]

The components of a vector, v, at angle \theta to a line, parallel and perpendicular to the line, form the legs of a right triangle having the vector as hypotenuse. Yes, the component parallel to the line is |v|cos(\theta). And just as obviously, the component perpendicular to the line is |v|sin(\theta)).

 

[Niles]

The components of a vector, v, at angle \theta to a line, parallel and perpendicular to the line, form the legs of a right triangle having the vector as hypotenuse. Yes, the component parallel to the line is |v|cos(\theta). And just as obviously, the component perpendicular to the line is |v|sin(\theta)).

Thanks for your reply. OK, I took an example to test this out. My (unit) vector is v = (0, v_y, v_z)/\sqrt{2} and the vector I want to project v onto is
<br /> u = (u_x, u_y, 0)<br />
The projection v onto u is then (disregarding the √2...)
<br /> u_y = \sqrt{u_x^2 + u_y^2}\cos \theta<br />
The perpendicular part is then given by \sin\theta, which must be given by (since sin² + cos² = 1...)
<br /> u_x = \sqrt{u_x^2 + u_y^2}\sin \theta<br />There is something I can't figure out - how can it be that there is no reference to any z-component in these expressions? I mean the above (perpendicular) sin-part only accounts for how much of v_y is perpendicular to u, it does not include the fact that v_z is also perpendicular. Is this something I have to manually add somehow? I hope you understand my question.

 

[HallsofIvy]

Well, I avoided mentioning components at all for exactly that reason. if \vec{u}= u_x\vec{ i}+ u_y\vec{j}+ u_z\vec{k} then its projection onto any line with which it makes angle \theta is |u|cos(\theta)= \sqrt{u_x^2+ u_y^2+ u_z^2} cos(\theta) and the length of the perpendicular is |u|sin(\theta)= \sqrt{u_x^2+ u_y^2+ u_z^2} sin(\theta)

 

[Niles]

OK, so just a generalization from 2D to 3D. Thanks for your help and time