Projection onto Column Space of A and its Perpendicular

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To compute the projection of vector b onto the column space of matrix A, one must first determine the column space by finding the reduced row echelon form of A. The column space is defined as the span of the columns of A, which can be confirmed through this process. For the perpendicular projection, it is essential to understand that any vector in the perpendicular space satisfies the condition of orthogonality with respect to the column space. Clarification on how to calculate the perpendicular projection involves using the concept of orthogonal complements and leveraging the properties of the dot product. Understanding these concepts will facilitate the solution to the problem.
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Homework Statement



Some of the details in this question are based off the use of matlab. If it's needed I can show the matrices that MATLAB creates.


Let A = magic(8); A = A(:,1:3) and let S be the Column Space of A. For b = [1:8]' compute the projection of b onto the Column Space of A. What is the projection of b perpendicular to the Column Space of A?



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The Attempt at a Solution



I'm not sure exactly where to get started. My first issue is that I'm not sure how to find the column space of A. I think I'm supposed to take the reduced row echelon form of the matrix and then shrink it if necessary. My book defines Column space as the span, so this would make sense to me.

I'm also not sure how to find the perpendicular of a matrix. I know it's defined such that v \in W^\perp => v \cdot u = 0 | u \in W but I'm not sure how to go from there.
 
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I'm fairly sure I'm right about the column space but I could use an explanation on perpendicular matrices if anyone can help.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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