Proof: if f holomorphic then f(z)=λz+c

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The discussion centers on proving that a holomorphic function \(f: \mathbb{C} \to \mathbb{C}\) of the form \(f(x+iy) = u(x) + i*v(y)\) can be expressed as \(f(z) = \lambda z + c\), where \(\lambda\) is a real number and \(c\) is a complex constant. The key to this proof lies in applying the Cauchy-Riemann equations, which are fundamental in complex analysis for establishing the relationship between the real and imaginary parts of holomorphic functions. The participants emphasize the necessity of these equations to derive the desired form of \(f(z)\).

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Seijo
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Hello. I need a bit of help or a hint maybe..

I am to show that if f: C -> C is a holomorphic function that is of the form f(x+iy) = u(x) + i*v(y) where u and v are real functions,
then f(z) = λz+c where λ is a real number and c is a complex one.

How would I begin to prove this?

Thanks to everyone in advance.
 
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Seijo said:
Hello. I need a bit of help or a hint maybe..

I am to show that if f: C -> C is a holomorphic function that is of the form f(x+iy) = u(x) + i*v(y) where u and v are real functions,
then f(z) = λz+c where λ is a real number and c is a complex one.

How would I begin to prove this?

Thanks to everyone in advance.

Hi Seijo, :)

Try using the Cauchy-Riemann equations since \(f\) is holomorphic.

Kind Regards,
Sudharaka.
 

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