Proof of a formula with two geometric random variables

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The discussion focuses on proving a formula involving two geometric random variables. The initial attempt at the solution is criticized for multiple-counting cases. The correct approach is to sum the cases where G_1 equals k, rather than where G_1 is less than or equal to k. This clarification is essential for accurately solving the problem. The emphasis is on correcting the method to avoid errors in counting.
Armine
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Homework Statement
If G_1 and G_2 are independent geometric random variables with parameters p_1 and p_2 respectively, show that
Relevant Equations
P(G_1<G_2)=p_1(1-p_2)/(p_1+p_2-p_1p_2)
The image above is the problem and the image below is the solution I have tried but failed.

MVIMG_20210209_102231_recompress.jpg
1612521305080_recompress.jpg
 
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You first equation is multiple-counting many cases. You should sum the cases where ##G_1 = k##, not ##G_1 \le k##
 
FactChecker said:
You first equation is multiple-counting many cases. You should sum the cases where ##G_1 = k##, not ##G_1 \le k##
Get it, thank you very much!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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