Proof of Fermat's Little Theorem: g Generator of Fp*

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views
jacquelinek
Messages
3
Reaction score
0
Prove that:
g is a generator of Fp* if and only if g^(p-1) = 1 (mod p) and gq ≠ 1 (mod p) for all prime divisors q of (p – 1).

I am thinking about applying Fermat's theorem...but don't know how...
Request help, thanks.
 
Physics news on Phys.org
Should that be gq?

Fermat's theorem may be useful for part of the proof. It certainly cannot prove this theorem all by itself.

What do you know about finite fields? And about their unit groups?