Proof of integral identity (popped up in a Fourier transform)

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SUMMARY

The integral identity presented is proven using contour integration techniques, specifically the Residue Theorem. The integral in question is defined as \int_{-\infty}^{\infty} \frac{sin(\gamma)}{cosh(\lambda)-cos(\gamma)} e^{i \omega \lambda}d \lambda, which simplifies to 2 \pi \frac{sinh(\omega(\pi-\gamma))}{sinh(\pi \omega)}. The discussion emphasizes the necessity of understanding complex analysis and the application of residues in evaluating integrals involving exponential functions.

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  • Complex analysis fundamentals
  • Residue Theorem application
  • Fourier transform properties
  • Understanding of hyperbolic functions
NEXT STEPS
  • Study the Residue Theorem in detail
  • Explore applications of contour integration in Fourier transforms
  • Learn about hyperbolic function identities and their properties
  • Practice solving integrals involving exponential functions and trigonometric components
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Mathematicians, physics students, and anyone involved in advanced calculus or complex analysis, particularly those focusing on integral transforms and residue calculations.

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Homework Statement



Prove;
[itex]\int_{-\infty}^{\infty} \frac{sin(\gamma)}{cosh(\lambda)-cos(\gamma)} e^{i \omega \lambda}d \lambda= 2 \pi \frac{sinh(\omega(\pi-\gamma))}{sinh(\pi \omega)}[/itex]

Homework Equations



Contour Integration/Residue Theorem?

The Attempt at a Solution


I have messed around with the exponential for a bit, but to no avail - I was thinking maybe the Residue theorem might play a part? I'm not really sure how to continue from here.
 
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any ideas? I am legitimately stumped on this one..
 

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