Proof of lower bound of a nonempty set of real numbers

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tronter
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1. Let [itex]A[/itex] be a nonempty set of real numbers which is bounded below. Let [itex]-A[/itex] be the set of numbers [itex]-x[/itex], where [itex]x \in A[/itex]. Prove that [itex]\inf(A) = -\sup(-A)[/itex].

Intuitively this makes sense if you draw it on a number line. But I am not sure how to formally prove it.
 
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tronter said:
1. Let [itex]A[/itex] be a nonempty set of real numbers which is bounded below. Let [itex]-A[/itex] be the set of numbers [itex]-x[/itex], where [itex]x \in A[/itex]. Prove that [itex]\inf(A) = -\sup(-A)[/itex].

Intuitively this makes sense if you draw it on a number line. But I am not sure how to formally prove it.

If -x is in -A then -x<sup(-A)
this implies:
x>-sup(-A)

Therefor -sup(-A) is a lower bound of A.

Now establish it is the least lower bound (probably via contradiction).