# Proof of lower bound of a nonempty set of real numbers

1. Feb 16, 2008

### tronter

1. Let $A$ be a nonempty set of real numbers which is bounded below. Let $-A$ be the set of numbers $-x$, where $x \in A$. Prove that $\inf(A) = -\sup(-A)$.

Intuitively this makes sense if you draw it on a number line. But I am not sure how to formally prove it.

2. Feb 16, 2008

### John Creighto

If -x is in -A then -x<sup(-A)
this implies:
x>-sup(-A)

Therefor -sup(-A) is a lower bound of A.

Now establish it is the least lower bound (probably via contradiction).