- #1
philnow
- 83
- 0
Homework Statement
I'm trying to derive the formula for the multiplicative inverse of a complex number. I say that:
z=a+bi
z-1=u+vi
and zz-1 must be 1 so
zz-1=(a+bi)(u+vi)
=(au-bv)+(av+bu)i
=1
So in order for zz-1=1, (au-bv) must be 1 and (av+bu) must be 0. My teacher has solved this as:
z-1= a/(a2+b2) - bi/(a2+b2)
I just don't know how to get that from au-bv=1 and av+bu=0
2. The attempt at a solution
Don't know how to get the last part... major brain fog. Please help?