Proof of Real Projective Plane Embedding in R4

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I'm working on a proof to show there exists an embedding of the real projective plane P R2 in R4.
The initial setup is as follows:
Let S2 denote the unit sphere in R3 given by S2 = {(x, y, z) ∈ R3 : x2 + y 2 + z 2 = 1}, and let
f : S2 → R4 be defined by f (x, y, z) = (x2 − y 2 , xy, yz, zx).
I'm trying to show that f determines a continuous map F: P R2 → R4 where P R2 is the real projective plane,
then show that F is a homeomorphism onto a topological subspace of R4 .
I think it's easy to see that f(x1,y1,z1)=f(x2,y2,z2) implies (x1,y1,z1)=+/-(x2,y2,z2). But I don't know how to figure out the whole proof completely. Could anyone please give me a hint? Any input is appreciated!
 
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Hi, Rain:

If a map is constant ( has a constant value) on equivalence classes, then we

say that the map passes to the quotient, i.e., that we can work out a commutative

diagram with one of the sets being S/~ , where ~ is the equivalence relation.

In your case, ~ is the quotient map defined on S^2 . Show that all (2) elements

in each equivalence class are sent to the same value, so that the other map

passes to the quotient.
 
q
S<sup>2</sup> ---->S<sup>2</sup>/~
/ |\
f / F
| \/
R<sup>4</sup>


Then the map you want is the only map that will make the above diagram commute
(double check everything, since I am kind of tired now.), a map

You can then use properties of the quotient topology, and the fact that a
continuous bijection between compact and Hausdorff is a homeomorphism,
to show the map is an embedding.


Does that Answer your Question.?
 
Hello! There is a simple line in the textbook. If ##S## is a manifold, an injectively immersed submanifold ##M## of ##S## is embedded if and only if ##M## is locally closed in ##S##. Recall the definition. M is locally closed if for each point ##x\in M## there open ##U\subset S## such that ##M\cap U## is closed in ##U##. Embedding to injective immesion is simple. The opposite direction is hard. Suppose I have ##N## as source manifold and ##f:N\rightarrow S## is the injective...

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