Proof of the properties of an ordered feild

  • Thread starter Thread starter EV33
  • Start date Start date
  • Tags Tags
    Proof Properties
EV33
Messages
192
Reaction score
0

Homework Statement


If F is an ordered field the the following property holds for any elements a and b of F.
If b<a, the -a<-b.

My task is to prove this property. My question is whether I need to use the definition of an ordered field. I used the basic axioms but I didn't use the definition of an ordered field.


Homework Equations


The basic axioms such... communitivity, addative inverse...
The definition of an ordered field.


The Attempt at a Solution



Assume b<a. Then add -a-b to each side, which gives us b-a-b<a-a-b. by using communitivity on the left we can rewrite it as b-b-a<a-a-b. By the use of the addative inverse we can simplify it to -a<-b.(QED)

So does this work without the definition of an ordered field?
 
Physics news on Phys.org
Those properties, commutativity etc are part of the definition of a field, aren't they?
 
And the fact that you can add the same thing to both sides of an inequality is part of the definition of an ordered field.
 
The "definition of an ordered field" is that it is a set of objects, together with two operations and an order relation, that satisfy those axioms!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top