Proof of Theorem: Composite Function Inverse

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Discussion Overview

The discussion centers around the proof of the theorem stating that if functions f and g are bijective, then the inverse of the composition of these functions (g o f) is equal to the composition of their inverses (inverse of f o inverse of g). The scope includes mathematical reasoning and proof techniques.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant requests the proof of the theorem regarding the inverse of composite functions.
  • Another participant offers a hint by suggesting to define f(x) = y and g(y) = z.
  • A different participant suggests computing (g o f) o (g o f)^-1 and (g o f)^-1 o (g o f) to demonstrate that both yield the identity function.

Areas of Agreement / Disagreement

The discussion does not show clear agreement or disagreement, as it primarily consists of requests for help and hints rather than established claims or proofs.

Contextual Notes

Participants have not provided specific assumptions or definitions that may affect the proof, and the steps of the proof remain unresolved.

irvin.b
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i really need to see the proof of this theorem:

if f and g are bijective then the inverse of (g o f) = inverse of f o inverse of g
 
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i hope you will help me..
 
what have you tried?
 
Hint: define f(x) = y and g(y) = z.
 
Just compute (g o f) o (g o f)^-1 and (g o f)^-1 o (g o f) and see that they both give you the identity.
 

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