Proof regarding Range of linear maps

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SUMMARY

The discussion centers on proving that for linear maps T and S from vector space V to finite-dimensional vector space W, the dimension of the range of their sum (S + T) is less than or equal to the sum of their individual ranges. Specifically, it establishes that dim(range(S + T)) ≤ dim(range S) + dim(range T). The participants clarify that S + T consists of all vectors of the form u + v, where u is in the range of S and v is in the range of T, and they explore the implications of the intersection of these ranges.

PREREQUISITES
  • Understanding of linear maps and vector spaces
  • Knowledge of dimension and range in linear algebra
  • Familiarity with subspaces and their properties
  • Concept of finite-dimensional spaces
NEXT STEPS
  • Study the properties of linear combinations of vector spaces
  • Learn about the Rank-Nullity Theorem in linear algebra
  • Explore the concept of direct sums of vector spaces
  • Investigate examples of linear maps and their ranges in finite-dimensional spaces
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Students and educators in linear algebra, mathematicians focusing on vector space theory, and anyone involved in the study of linear transformations and their properties.

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Homework Statement



Prove that if T, S : V -> W are linear and W is finite dimensional then
dim (range(S + T)) <= dim range S + dim range T


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The Attempt at a Solution



I know that the dim range S + dim range T can be at most 2 * dim W. However, I'm a little stuck on trying to figure out what dim (range(S+T)) is. How do I determine S + T?
 
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Suppose Range S and Range T have only the 0 vector in common. What is S+ T? If they have more than the 0 vector in common, their intersection must be a subspace.

Or is the problem that you do not know how S+ T is defined? It is the space of all vectors orf the form u+ v where u is in S and v is in T.
 

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