Proof that the adjoint representation is an endomorphism

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SUMMARY

The discussion centers on the adjoint representation of a Lie group and its algebra, specifically addressing the expression ##AXA^{-1}## and its implications. The user seeks clarification on the expansion of ##\exp(tAXA^{-1})## and the general behavior of functions like ##f(AXA^{-1})## under Taylor expansion. The conclusion drawn is that ##\exp(tAXA^{-1})## can be expressed as ##A(\exp{tX})A^{-1}##, confirming that it remains within the group ##G##.

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Homework Statement


My textbooks takes for granted that, given a Lie group ##g## and its algebra ##\mathfrak{g}##, we have that ##AXA^{-1} \in \mathfrak{g}##.

Homework Equations


For ##Y## to be in ##\mathfrak{g}## means that ##e^{tY} \in G## for each ##t \in \mathbf{R}##

The Attempt at a Solution


I tried to expand ##\exp(tAXA^{-1})## but I am stuck, since the term inside the exponential is a mix of group and algebra matrices and I don't know how to deal with it.
 
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What can you say in general for a function ##f(AXA^{-1})## assuming it can be Taylor expanded?

Edit: Or rather, what is ##(A X A^{-1})^n##?
 
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Orodruin said:
What can you say in general for a function ##f(AXA^{-1})## assuming it can be Taylor expanded?

Edit: Or rather, what is ##(A X A^{-1})^n##?

Thanks! So:
##\exp (tAXA^{-1}) = 1 + tAXA^{-1} + \frac{t^2}{2}AX^2A^{-1} + ... = A(\exp{tX})A^{-1} \in G##

Why I was stuck, I don't understand... Thank you for the hint!
 

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