Proofing Derivatives: fg''-f''g=(fg'-f'g)' & fg''+f''g=(fg)

  • Thread starter Thread starter lax1113
  • Start date Start date
  • Tags Tags
    Derivative Proof
Click For Summary

Homework Help Overview

The discussion revolves around proving two derivative identities involving functions f and g. The identities in question are a) fg'' - f''g = (fg' - f'g)' and b) fg'' + f''g = (fg)''. The subject area is calculus, specifically focusing on derivatives and the product rule.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the validity of the identities by substituting specific functions and express uncertainty about the proof process. Some suggest using the product rule instead of numerical substitution. Questions arise regarding the interpretation of taking derivatives of the functions involved.

Discussion Status

There is an ongoing exploration of the identities, with some participants indicating a shift in understanding after receiving guidance. While one participant expresses confusion, another acknowledges a clearer grasp of the concepts. There is no explicit consensus on the outcomes of the identities, but some productive direction has been provided.

Contextual Notes

Participants mention feeling overwhelmed due to other academic pressures, which may affect their focus and understanding of the problem at hand.

lax1113
Messages
171
Reaction score
0

Homework Statement


is a) fg''-f''g=(fg'-f'g)'
b) fg''+f''g=(fg)''


Homework Equations


product formula? f'g+fg'=fg'
quotient rule- (f'g-fg')/g^2=(f/g)'



The Attempt at a Solution


All i did was plug in numbers, such that f=x^3 and g=x^2 and then solved it that way. For doing this, I got that a is true and that b is false, but it isn't really a proof if you use numbers, hell it isn't a proof at all. :smile: Any ideas on how to make it so that it either IS or ISNT true.
 
Physics news on Phys.org
lax1113 said:

Homework Statement


is a) fg''-f''g=(fg'-f'g)'
b) fg''+f''g=(fg)''


Homework Equations


product formula? f'g+fg'=fg'
quotient rule- (f'g-fg')/g^2=(f/g)'



The Attempt at a Solution


All i did was plug in numbers, such that f=x^3 and g=x^2 and then solved it that way. For doing this, I got that a is true and that b is false, but it isn't really a proof if you use numbers, hell it isn't a proof at all. :smile: Any ideas on how to make it so that it either IS or ISNT true.
Instead of "plugging in numbers" (you're actually plugging in functions, not numbers), just use the product rule.

Problem a (reading from right to left) says that the derivative of fg' - f'g is what is shown on the left. What is the derivative of fg' - f'g.

Problem b (again reading from right to left) says that the 2nd derivative of fg is shown on the left. Take the derivative of fg and see what you get. Take the derivative of that and see what you get.
 
Mark,
What i don't understand is how can i just take the derivative of f and g?
We know all the rules, but i don't get what you mean by take the derivative of it.
 
Sorry mark,
I completely understand now, makes no sense why i didnt do it before. I have been making stupid mistaes like this for the past two days, I have a huge problem set due for math physics and a big research paper due, so I am kinda just burnt out i guess. Thanks tho for the nudge mark.


just to check, i got the first one being equal, second one not being equal?
 
lax1113 said:
Sorry mark,
I completely understand now, makes no sense why i didnt do it before. I have been making stupid mistaes like this for the past two days, I have a huge problem set due for math physics and a big research paper due, so I am kinda just burnt out i guess. Thanks tho for the nudge mark.


just to check, i got the first one being equal, second one not being equal?

I didn't work the first one, but it's pretty easy now that you know how. I worked the second one and agree that the two expressions aren't equal.
 

Similar threads

Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 39 ·
2
Replies
39
Views
6K