Can Proportional Variation be Deduced Algebraically from Given Equations?

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Proportional variation among variables A, B, and C can be algebraically deduced from the equations A = kB and A = iC by recognizing that both k and i are functions of their respective constants. By keeping C constant in the first equation and B constant in the second, it is established that A is proportional to both B and C. This leads to the conclusion that A = jBC, where j represents a constant of proportionality. The relationship implies that if B and C are independent, then k must be proportional to C and i must be proportional to B. Thus, the algebraic deduction of A = jBC follows logically from the initial observations.
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Consider the following situation :

There are three variables A, B and C. (and i,j,k are constants )
Keeping C constant, and varying the other two, you find that

A = kB ------(1)

Now, Keeping B constant, and varying the other two, you find that

A = iC ------(2)

I know that it follows from these two observations that

A = jBC

But I am not sure how we can algebraically deduce this from the equations (1) and (2).

We get A^2 = ikBC

Presumably, ik = \sqrt{j}BC
But how do we deduce this?
 
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You have

A = k(C) \times B = i(B) \times C

where k and i are functions of C and B, respectively. If B and C are independent variables then the only way k(C)B and i(B)C can be equal is if k is proportional to C and i is proportional to B. Therefore, A = jBC.
 
Thanks for the help.
 
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