Proton enters magnetic field in spiral trajectory

Click For Summary
A proton moving in a 5 T magnetic field follows a spiral path with a pitch of 5 cm, indicating the distance it moves vertically after one complete revolution. The discussion emphasizes the need to break down the velocity into two components: one perpendicular and one parallel to the magnetic field. The relationship between the pitch, velocity, and time period for one revolution is crucial for finding the angle between the velocity and the magnetic field. However, additional information such as speed or radius is necessary to solve for the angle. The conversation highlights the importance of understanding the components of motion in magnetic fields.
songoku
Messages
2,507
Reaction score
402

Homework Statement


A proton moves in a spiral path when enters a magnetic field of 5 T. If the pitch is 5 cm, find the angle between v and B.


Homework Equations


F = B q v sin θ
F = m v2 / r


The Attempt at a Solution


I am guessing that I need to break down the velocity into two components but still don't know how to use it. What is pitch actually?

Thanks
 
Physics news on Phys.org
That is it went 5 cm up or down after one revolution.
 
The pitch of a spiral is the distance moved after one complete revolution.
The diagram in section 2.5 of this wiki article is fairly clear:-
http://en.wikipedia.org/wiki/Screw_thread

The two velocity components would be
vsinθ perpendicular to B
vcosθ parallel to B

vsinθ should be used in both the equations you give not just the first one.
The two forces can then be equated.
The pitch of the spiral is equal to vcosθ x (time period for one revolution, T) ie distance=speed x time
But T also is equal to 2πr/vsinθ.

Using the above ideas I found an expression for θ that still had one unknown in it. Is there any other information given in the question?
 
Basic_Physics said:
That is it went 5 cm up or down after one revolution.

apelling said:
The pitch of a spiral is the distance moved after one complete revolution.
The diagram in section 2.5 of this wiki article is fairly clear:-
http://en.wikipedia.org/wiki/Screw_thread

The two velocity components would be
vsinθ perpendicular to B
vcosθ parallel to B

vsinθ should be used in both the equations you give not just the first one.
The two forces can then be equated.
The pitch of the spiral is equal to vcosθ x (time period for one revolution, T) ie distance=speed x time
But T also is equal to 2πr/vsinθ.

Using the above ideas I found an expression for θ that still had one unknown in it. Is there any other information given in the question?

That's all the information given. I get your idea. We have to know either the speed or radius to be able to solve for angle.

Thanks a lot for your help :)
 

Similar threads

Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
926
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 1 ·
Replies
1
Views
11K
Replies
8
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
3
Views
2K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 21 ·
Replies
21
Views
3K