Proton Motion in Electric Field

[XTEND]

Homework Statement

2 large metal sheets are separated by a potential of 40 volts by a vaccum. When the proton particle (mass 1.67x10e-27 kg)is released close to the (+) sheet it moves closer to the (-) sheet by way of electric field. What's the KE right before the proton smacks the other sheet? And what's the velocity of before striking the (-) sheet?

Homework Equations

KE=>q*v and EK=mv^2/2

The Attempt at a Solution

KE= 1.6x10e-19(40)=6.4x10e-18

v= ?

 

[jgens]

What's the formula for the kinetic energy of an object (in terms of the object's velocity)?

 

[XTEND]

Can anyone help me with this?

I think the velocity is 87548 m/s. Is this correct?

 

[rl.bhat]

Can anyone help me with this?

I think the velocity is 87548 m/s. Is this correct?

Your answer is correct.

 

[XTEND]

what about the first part for KE?

 

[ideasrule]

what about the first part for KE?

If that isn't correct, you wouldn't have gotten the right answer for v. So yes, KE=qV, and your calculation is right as well.