How Does the Proton-Proton Cycle Result in the Formation of Helium?

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The discussion clarifies the proton-proton cycle in nuclear fusion, where six protons ultimately fuse to create two helium-3 nuclei, which then combine to form helium-4 and release two protons. The confusion arises from the representation of the reaction, as some members question why only four protons are mentioned in the final equation. The net reaction can be simplified by omitting intermediate products, leading to the equation 6 1H → 4He + 2 1H, which accounts for the protons involved. This approach helps clarify the fusion process while maintaining the conservation of mass and energy. Overall, the thread emphasizes understanding the fusion process and the significance of intermediate steps in nuclear reactions.
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Homework Statement



Dear members,
In proton proton cycle, Two protons fuse together to form a duetron with positron and nuetrino.
Then duetron combine with another proton to form 2He3, which then combines with another 2He3 to give 2He4
The final reaction is
41H1+2e---> 2He4

Homework Equations





3. The Attempt at a Solution
Only three protons fuse together in the process, then how in the final equation it has been stated 4 protons fuse. For 2He3 to combine with 2He3 , the reaction of proton fusing with another proton, giving duetron, which fusing with another proton, should happen twice. So it is 6 protons fusing. So why its been mentioned only 4 protons fuse to form helium. Please help revered members



 

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logearav said:
3. The Attempt at a Solution
Only three protons fuse together in the process, then how in the final equation it has been stated 4 protons fuse. For 2He3 to combine with 2He3 , the reaction of proton fusing with another proton, giving duetron, which fusing with another proton, should happen twice. So it is 6 protons fusing. So why its been mentioned only 4 protons fuse to form helium. Please help revered members


6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.

Alternatively, you might write a net reaction that doesn't include 2 of the original 6 protons -- in which case you wouldn't have the 2 protons that are left over in the end.
 
6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.

Redbelly98 said:
Alternatively, you might write a net reaction that doesn't include 2 of the original 6 protons -- in which case you wouldn't have the 2 protons that are left over in the end.
Thanks for the reply sir. But i didnt understand the lines quoted above.
 
Is this a homework problem? I am having trouble understanding exactly what the problem is asking, or whether you are just trying to understand for yourself what happens in nuclear fusion.
 
Sir, i am asking to get clarified, because my teacher has not given satisfactory reply. I got 90% of what you said, but i can't understand the lines you have written which i quoted in my previous query.
Thanks again. This is the forum which gives excellent insights to physics, that's why i keep raising my query
 
logearav said:
6 protons fuse to form 2 helium-3 nuclei. Then the two helium-3 nuclei form helium-4 plus 2 protons.
Okay, so omit the intermediate products (He-3 nuclei) and write that as
6 1H → 4He + 2 1H (+ energy, positrons, and neutrinos)​
We have hydrogen nuclei on both sides of the reaction, so we can take away 21H from each side. That leaves us with the net reaction.
 
Mr.Redbelly, Fantastic. I got it now. Thank you so much, sir
 
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