- #1

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Can anyone help me solving this problem?

I have tried to set up the mean value theorem, but i just do not know how to proceed.

- Thread starter Charlotte87
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- #1

- 21

- 0

Can anyone help me solving this problem?

I have tried to set up the mean value theorem, but i just do not know how to proceed.

- #2

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It is rather obvious even without the mean value theorem. Just multiply and divide by the conjugate.

- #3

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- #4

HallsofIvy

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[tex]\frac{f(b)- f(a)}{b- a}= f'(c)[/tex].

Take f(x)= x

- #5

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Am I right with my reasoning below: this proves my limit, since lim(f(b)-f(a))=lim(f'(c)*(b-a))=0 since f'(c)=0?