Prove d || d' in Figure with A = A' = 90

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To prove that lines d and d' are parallel in the given figure, one can utilize the properties of angles formed by a transversal. Since angles A and A' are both 90 degrees, they are corresponding angles. According to the theorem, if corresponding angles are congruent, the lines crossed by the transversal are parallel. Therefore, it can be concluded that d is parallel to d'. Understanding these geometric principles is essential for solving similar problems.
Behrooz
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hi,could u please help me with this Geometrical problem?
in this figure prove that : d||d'
Heres the figure:
as u see A=90 and so is A'
 

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What do you have to work with? That is, what theorems about parallel lines do you know and can use? For example do you know "If 'corresponding angles' formed by a transversal crossing two lines are congruent, then the lines are parallel"? Or "If 'alternate interior angles' formed by a transversal crossing to lines are congruent then the lines are parallel"? If you know those, then you should be able to apply one to this problem.
 

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