Prove expansibility / isothermal compressibility

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SUMMARY

The discussion focuses on proving the relationship between expansibility (β) and isothermal compressibility (κ) in thermodynamics, specifically demonstrating that (∂P/∂T) at constant volume equals (β/κ). Expansibility is defined as (1/V)(∂V/∂T) at constant temperature, while isothermal compressibility is defined as (-1/V)(∂V/∂P) at constant pressure. The proof involves manipulating the differential volume equation, dV = (∂V/∂T)PdT + (∂V/∂P)TdP, and setting dV to zero to isolate (∂P/∂T) at constant volume.

PREREQUISITES
  • Understanding of thermodynamic concepts such as expansibility and isothermal compressibility.
  • Familiarity with partial derivatives and their application in thermodynamics.
  • Knowledge of differential equations in the context of physical systems.
  • Basic principles of thermodynamic variables like pressure (P), volume (V), and temperature (T).
NEXT STEPS
  • Study the derivation of the Maxwell relations in thermodynamics.
  • Explore the implications of the relationship between β and κ in real gases.
  • Learn about the applications of expansibility and compressibility in material science.
  • Investigate the role of temperature and pressure in phase transitions.
USEFUL FOR

Students and professionals in thermodynamics, physicists, and engineers interested in the properties of materials under varying temperature and pressure conditions.

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β is expansibility , (1/V)(∂V/∂T) at constant temperature
κ is isothermal compressibility , (-1/V)(∂V/∂P) at constant pressure

How to prove (∂P/∂T) at constant V = (β/κ)
Thank you
 
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Outrageous said:
β is expansibility , (1/V)(∂V/∂T) at constant temperature
κ is isothermal compressibility , (-1/V)(∂V/∂P) at constant pressure

How to prove (∂P/∂T) at constant V = (β/κ)
Thank you

dV = (∂V/∂T)PdT + (∂V/∂P)TdP

set dV = 0 to evaluate (∂P/∂T)V
 
Chestermiller said:
dV = (∂V/∂T)PdT + (∂V/∂P)TdP

set dV = 0 to evaluate (∂P/∂T)V


Understand. Thank you
 

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