Prove how focus of a spherical mirror = Radius of curvature/2

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SUMMARY

The focal length of a spherical mirror is definitively established as half the radius of curvature, expressed mathematically as ffl = R/2. This conclusion is derived using the thin lens formula: 1/fo + 1/fi = 1/ffl, where both object distance (fo) and image distance (fi) equal the radius of curvature (R). The discussion also addresses scenarios where the object distance does not equal the image distance, confirming that when the object is at infinity, the image distance simplifies to fi = R/2.

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  • Understanding of the thin lens formula
  • Knowledge of spherical mirrors and their properties
  • Familiarity with concepts of object distance and image distance
  • Basic principles of optics
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amanara
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Prove how focus of a spherical mirror = Radius of curvature/2
 
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The quickest way (only approximate) is to use thin lens formulas:
Use fo = object distance; fi = image distance; and ffl = focal length.
So 1/fo + 1/fi = 1/ffl [basic thin lens formula]
If both fo and fi = R (radius of curvature)
then 1/R + 1/R = 1/ffl = 2/R
So ffl = R/2
 
but what if the object distance is not equal to image distance?
 
Does this help?

Mirror Equation (in particular the bottom section)

(I found this by a Google search for "focal length of a spherical mirror".)
 
amanara said:
but what if the object distance is not equal to image distance?
We know that if the object is at the center of radius of curvature R, then the image is also at the center of radius of curvature. So fo = fi = R

Using the thin lens formula 1/fo + 1/fi = 1/ffl
Substituting R we get
1/R + 1/R = 1/ffl
So 2/R = 1/ffl
Now suppose the object is at infinity
1/inf. + 1/fi = 1/ffl = 2/R
then fi = R/2
 
Last edited:

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