(adsbygoogle = window.adsbygoogle || []).push({}); 1. if there is a number B such that abs|f(x)| <= B for all x#0, then lim as x->0 of xf(x) = 0,

2. Would I be able to get some help on how to prove this?

3. Given Epsilon > 0 such that delta = epsilon/B will prove the limit equals 0. (I know that may not make much sense but how am I supposed to make a solution when I don't know where to start... but I was warned so here is my attempt.) :|

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# Homework Help: Prove if abs|f(x)| <= B for all x#0, then lim as x->0 of xf(x) = 0,

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