Prove Inequality: a,b,c ∈R+ | n≥1

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The discussion focuses on proving the inequality involving positive real numbers a, b, and c, and a natural number n. Participants suggest using mathematical induction as a method for the proof. The initial step involves verifying the case for n=1, where the inequality holds true. It is emphasized that proving the statement for n=2 is not sufficient; one must also demonstrate its validity for n=k+1 after assuming it holds for n=k. The conversation highlights the importance of understanding the induction process to complete the proof successfully.
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Homework Statement



Prove \frac{a^{n+1}}{b+c}+\frac{b^{n+1}}{a+c}+\frac{c^{n+1}}{a+b}=(\frac{a^{n}}{b+c}+\frac{b^{n}}{a+c}+\frac{c^{n}}{a+b})*\sqrt[n]{\frac{a^{n}+b^{n}+c^{n}}{3}}
if n>=1 and a,b,c \in\textsl{R}_{+}

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The Attempt at a Solution


I tried prove it i some ways but i think any of it don't approach me to solution. I need a clue, don't give me solution.

PS sorry for my english
 
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Clue: mathematical induction
 
Mathematical Induction is a method of proving a series of mathematical statement labelled by natural numbers
 
Right, and aren't your values of n natural numbers? There is no such restriction on a, b, and c.
 
I get

a^{2}+b^{2}+c^{2}\geq ab+bc+ac for n=1
is it true?
what is next step(i never used mathematical induction before)

if i do it for n=2 it will be proved?
 
Last edited:
For n = 1 you have to show that
\frac{a^{2}}{b+c}+\frac{b^{2}}{a+c}+\frac{c^{2}}{a+b}=(\frac{a^{1}}{b+c}+\frac{b^{1}}{a+c}+\frac{c^{1}}{a+b})*\frac{a^{1}+b^{1}+c^{1}}{3}

It is not sufficient to quit after showing that the original statement is true for n = 2.

In mathematical induction, you assume that the statement is true for n = k, and use that to show that the statement is also true for n = k + 1.
 
Thanks for helping me.
 
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