Prove Nonempty Subset Sum of 5 Distinct Single-Digit Integers

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To prove that it's impossible to have a set B of 5 distinct positive single-digit integers where every nonempty subset has a different sum, the discussion highlights the application of the pigeonhole principle. With 5 distinct integers, there are 31 possible nonempty subset sums. However, the maximum sum achievable with the largest 4 distinct single-digit integers (9, 8, 7, 6) is 28. This indicates that there are more sums than possible distinct values, leading to the conclusion that at least two subsets must share a sum. The approach using the pigeonhole principle effectively demonstrates the impossibility of such a set existing.
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No idea where to start with this one...to prove that it is not possible to have a set B of 5 distinct positive single-digit integers such that every possible nonempty subset of B has a different sum. How do I approach it/do it?
 
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Given 5 distinct numbers, there are 2^5 - 1 possible sums of subsets, excluding the sum of all 5 which is 31.

However, the biggest possible sum of 4 distinct single digit numbres is 9+8+7+6= 28, so apply the pigeon hole principle.
 
I'll try that, thanks for the suggestion!
 
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