Prove Schwarz Inequality for x, y, z in R+

Pushoam
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Homework Statement


For x,y,z ## \in \mathbb {R^+} ##, prove that
## \sqrt {x (3 x +y) } + \sqrt {y (3y +z) } + \sqrt {z(3z +x)} \leq ~ 2(x +y+ z) ##

Homework Equations


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The Attempt at a Solution


I don't know which inequality among the above two has to be applied.
I am trying to solve it by inspection. I don't know the standard approach to solve it.
 

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If in doubt, write the Schwarz inequality with components of general vectors v,w, expand the smaller side, then see if you can assign the components to get these square roots at a suitable spot in the equation.
 
mfb said:
If in doubt, write the Schwarz inequality with components of general vectors v,w, expand the smaller side, then see if you can assign the components to get these square roots at a suitable spot in the equation.

I did it. Thanks a lot for guiding me.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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