Prove that e^c = sinh(1) for some c in [-1,1]

  • Thread starter Thread starter ruby_duby
  • Start date Start date
ruby_duby
Messages
46
Reaction score
0

Homework Statement



Assuming that (ex)’ = (ex) at all point x, prove that ec
= sinh(1) for some point C \in (-1,1). Give the full proof.

Homework Equations


The Attempt at a Solution



I honestly don't know how to attempt this. i can show that (ex)’ = (ex) by:

(ex) = 1 + x + x2/2! + x3/3! + x4! + x5/5! +...

(ex)’ = 1 + x + x2/2! + x3/3! + x4! + x5/5! +...

I just don't know how to tackle the sinh part of the equation.

I would really appreciate any help/ guidance
 
Physics news on Phys.org


Don't try series. Try Mean Value Theorem.

And don't forget the definition of sinh.
 


thanks so much, I've managed to work out the answer, however, does anyone know if i need to find a specific value for c?
 


Usually you don't, but if you do it's easy enough:

e^c=sinh(1), so c=ln(sinh(1))
 


ruby_duby said:
thanks so much, I've managed to work out the answer, however, does anyone know if i need to find a specific value for c?

You were only asked to show that it exists, not to actually give it (often in mathematics, it's easier to prove that you can construct or find it, than to actually do it).
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top