Prove that X U Y is countable infinite.

  • Thread starter Thread starter Nexttime35
  • Start date Start date
  • Tags Tags
    Infinite
Nexttime35
Messages
46
Reaction score
1

Homework Statement



attachment.php?attachmentid=59098&stc=1&d=1369787409.jpg


Homework Equations



Countable Infinite is defined if X is infinite and X is isomorphic to the Natural Numbers.

The Attempt at a Solution



Now I assume that XUY is isomorphic to the Natural Numbers. So X ∪ Y ≅ N .

Now here's where I get confused. I am unsure how to define a function that is invertible (to prove the bijection of being 1-1 and onto). Does anyone have an idea on where to go with this proof?
Thank you,
G.
 

Attachments

  • countable infinite (2).jpg
    countable infinite (2).jpg
    6 KB · Views: 667
Physics news on Phys.org
Nexttime35 said:

Homework Statement



attachment.php?attachmentid=59098&stc=1&d=1369787409.jpg


Homework Equations



Countable Infinite is defined if X is infinite and X is isomorphic to the Natural Numbers.

The Attempt at a Solution



Now I assume that XUY is isomorphic to the Natural Numbers. So X ∪ Y ≅ N .

Now here's where I get confused. I am unsure how to define a function that is invertible (to prove the bijection of being 1-1 and onto). Does anyone have an idea on where to go with this proof?
Thank you,
G.

You don't start by assuming XuY is countable. That's what you want to prove. Suppose X and Y are disjoint. If X ≅ N then there is a bijection f:N->X so you can write X={f(1),f(2),f(3),...}. Similarly Y={g(1),g(2),g(3),...}. Can you define a bijection h:N->XuY? Think of an h mapping even numbers to X and all of the odd numbers to Y.
 
Ahh, ok, that definitely makes sense. Thank you for the guidance.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top