In the discussion, the geometric problem involves proving that within triangle ABC, with point P located inside, at least one of the angles PAB, PBC, or PCA must measure 30 degrees or less. The reasoning is based on the property that the sum of angles in a triangle is 180 degrees. When the angles A, B, and C are equal (60 degrees each), the smallest angle cannot exceed 60 degrees. If any angle exceeds 60 degrees, the smallest angle must be less than 60 degrees, leading to the conclusion that at least one of the angles involving point P must be 30 degrees or less. The discussion references the 1991 International Mathematical Olympiad (IMO) and includes a request for resources on past IMO questions.