Proving a+b=b+a Using Ring Axioms

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SUMMARY

The discussion focuses on proving the commutative property of addition in ring theory, specifically demonstrating that a + b = b + a using ring axioms. Participants emphasize the importance of the distributive law and the identity elements, 0 and 1, in the proof. The solution involves manipulating the expression (1 + 1)(a + b) and expanding it in two different ways to illustrate the equality. This approach confirms that the commutative property is a consequence of the fundamental properties of rings.

PREREQUISITES
  • Understanding of ring theory and its axioms
  • Familiarity with algebraic manipulation techniques
  • Knowledge of the distributive law in mathematics
  • Concept of identity elements in algebra (0 and 1)
NEXT STEPS
  • Study the properties of ring axioms in detail
  • Learn about the distributive law and its applications in algebra
  • Explore examples of commutative rings and their characteristics
  • Investigate the role of identity elements in various algebraic structures
USEFUL FOR

Students of abstract algebra, mathematicians interested in ring theory, and educators teaching algebraic structures will benefit from this discussion.

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Homework Statement



Show that a+b = b+a follows from the other ring axioms.

Homework Equations



a + 0 = 0 + a = a (?)

The Attempt at a Solution


I know this is probably a simple algebraic manipulation, probably with the distributive law, but I don't know how to start! I'm sure I need some 1s and 0s somewhere.

Thanks!
 
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(1+1)(a+b)

Try expanding in two different ways
 

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