Mason98
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No Effort - Member warned that some effort must be shown
- Homework Statement
- Boolean algebra help
- Relevant Equations
- A.(a+b) = a
I thought it could possibly be A.B + A.C but I am not sure tbhcnh1995 said:What do you get when you use the distributive property here?
PS: Forum rules require you to show your attempt at a solution. We can only help by providing hints and pointing mistakes in your work.
Where is C in that expression?Mason98 said:I thought it could possibly be A.B + A.C but I am not sure tbh
Right.Mason98 said:A.A + A.B i mean sorry
Would i now use the Idempotent Law, which would change A.A to just A which would leave me with A +A.B and the A.B would change to B.A, so A + B.A ?cnh1995 said:Right.
You need to use the laws of boolean algebra to simplify this expression. The distributive property was one of these laws. How will you reduce this further?
Can you find anything in your lecture notes?
Right.Mason98 said:Would i now use the Idempotent Law, which would change A.A to just A which would leave me with A +A.B?
No need to change A.B to B.A.Mason98 said:and the A.B would change to B.A, so A + B.A ?
Hmm thanks for the help by the way appreciate it :), I'm thinking it could be, A.1 + A.B?cnh1995 said:No need to change A.B to B.A.
Hint (if you haven't got the next step yet): A=A.1
Now factor the expression, using the reverse of the distributive law. What do you get?Mason98 said:Hmm thanks for the help by the way appreciate it :), I'm thinking it could be, A.1 + A.B?
A.(1+B)?Mark44 said:Now factor the expression, using the reverse of the distributive law. What do you get?
Right, and how can ##1 + B## be simplified? Remember that + is used for OR, so in terms of sets, this would be ##U \cup B##, where U is the universal set.Mason98 said:A.(1+B)?
Mason98 said:1 + B is basically 1 or B? So, it can be simplified down to just 1? I'm so confused