Proving A Must Be of Rank 2: The 2x2 Matrix Dilemma

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SUMMARY

The discussion centers on the necessity of proving that matrix A must be of rank 2 within the context of a specific theorem. Participants clarify that while the premise states A has rank 2, the theorem holds true for any matrix, not exclusively for rank-2 matrices. The consensus is that the proof provided successfully addresses the requirements of the problem, despite the initial confusion regarding the premise.

PREREQUISITES
  • Understanding of matrix rank and its implications in linear algebra.
  • Familiarity with theorems related to matrix properties.
  • Basic knowledge of proof techniques in mathematics.
  • Experience with 2x2 matrices and their characteristics.
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  • Study the properties of matrix rank and its significance in linear transformations.
  • Explore theorems applicable to matrices of different ranks.
  • Learn about proof strategies in linear algebra, focusing on direct and indirect proofs.
  • Investigate the implications of matrix rank in real-world applications, such as systems of equations.
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Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking to clarify concepts related to matrix rank and theorem proofs.

LukasMont
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Homework Statement
4.1 Show that one may express any second rank matrix as the sum of a symmetric
and an antisymmetric matrix.
Relevant Equations
I was able to proof that any matrix could be constructed by adding a symmetric and antisymmetric matrix:

A= A/2 + A/2 + A'/2 - A'/2,
A= (A/2 + A'/2) + (A/2 - A'/2), where A' is the transposed matrix. Now,

A/2 + A'/2 is symmetric, since (A/2 +A'/2)' = A'/2 + A/2 (equal) and
A/2 - A'/2 is antisymmetric, since (A/2 - A'/2)' = - A'/2 + A/2= -(A/2 - A'/2).
My trouble is being to show A must be of rank 2. Any ideas?
 
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You don't have to show that A has rank 2. You are given that as a premise.
I don't know why they give you that as a premise though, because the theorem is true for any matrix, not just any rank-2 matrix, as your proof shows.
Anyway, you have proven what they asked you to.
 
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