Proving a Sinh(x) expression to be an integer

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SUMMARY

The discussion centers on proving that sinh²(ln(√2 + √3)) equals 2. A participant confirmed this result using a calculator but sought a proof without computational tools. The approach involved rewriting sinh² using the identity (1/4)(e²x + e⁻²x - 2) and applying logarithmic properties. The next step suggested was to utilize the identity exp(ln(x)) = x to simplify the expression further.

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Prove or disprove: sinh2(ln([tex]\sqrt{}2[/tex]+[tex]\sqrt{}3[/tex])) is an integerObviously, I used my calc to figure out that the answer is 2. Proving it w/o a calc is hard though.

The Attempt at a Solution



I've tried rewriting sinh2 as (1/4)(e2x+e-2x-2) and after all the substitutions and log rules I get (1/4)(ln([tex]\sqrt{}2[/tex]+[tex]\sqrt{}3[/tex])+1/(ln([tex]\sqrt{}2[/tex]+[tex]\sqrt{}3[/tex]))-2)

what now?...
 
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Use the identity

[tex] \exp{(\ln{x})}=x[/tex]

to eliminate exp and ln.

ehild
 

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