Proving Absolute Convergence of a Real-Valued Function on a Sigma Algebra

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SUMMARY

The discussion establishes that for a real-valued function $f$ defined on a sigma algebra R, if the sum of $f(A_{n})$ over a sequence of disjoint members $A_{n}$ equals the image of the countable union under $f$, then this sum is absolutely convergent. The boundedness of $f$ is confirmed, with a constant M ensuring that |$f(A_{n})| \leq M$ for all n. By applying the Principle of Finite Sums, it is demonstrated that the sequence of partial sums is both increasing and bounded above, leading to the conclusion of absolute convergence.

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  • Understanding of sigma algebras in measure theory
  • Familiarity with real-valued functions and their properties
  • Knowledge of convergence concepts in mathematical analysis
  • Proficiency in the Principle of Finite Sums
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  • Study the properties of sigma algebras and their applications in measure theory
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  • Investigate the Principle of Finite Sums and its role in convergence proofs
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Let R be a sigma algebra and let $f$ be a real value function on R such that for a sequence
($A_{n}$) of disjoint members of R, we have that the sum of $f$($A_{n}$) over all n is equal to the image of the countable union under $f$. Prove that the sum of $f$($A_{n}$) is in fact absolutely convergent.
 
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Since $f$ is a real-valued function, it must be bounded. That is, there exists a constant M such that |$f$($A_{n}$)| $\leq$ M for all n. By the Principle of Finite Sums, we know that the sum of a sequence of finitely many non-negative real numbers is convergent if and only if the sequence of partial sums is increasing and bounded above. Since the sum of $f$($A_{n}$) over all n is equal to the image of the countable union under $f$, the sequence of partial sums is increasing and bounded above by M. Therefore, the sum of $f$($A_{n}$) is absolutely convergent.
 

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