Proving an Equation Involving k: A Homework Challenge

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SUMMARY

The equation k=\frac{1+\sin x}{\cos x} can be proven by manipulating its reciprocal. By inverting k, we obtain \frac{1}{k}=\frac{\cos x}{1+\sin x}. To simplify this expression, multiply both the numerator and denominator by (1-\sin x), leading to the desired result \frac{1}{k}=\frac{1-\sin x}{\cos x}. This method effectively demonstrates the relationship between the two expressions.

PREREQUISITES
  • Understanding of trigonometric identities, specifically sine and cosine functions.
  • Familiarity with algebraic manipulation of fractions.
  • Knowledge of the Pythagorean identity: sin²(x) + cos²(x) = 1.
  • Ability to perform substitutions in trigonometric equations.
NEXT STEPS
  • Study trigonometric identities and their proofs, focusing on sine and cosine relationships.
  • Learn about algebraic techniques for simplifying rational expressions.
  • Explore the use of reciprocal identities in trigonometry.
  • Practice solving similar trigonometric equations to reinforce understanding.
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Students studying trigonometry, mathematics educators, and anyone seeking to improve their skills in algebraic manipulation of trigonometric expressions.

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Homework Statement


k=[tex]\frac{1+sinx}{cosx}[/tex]
prove that [tex]\frac{1}{k}[/tex]=[tex]\frac{1-sinx}{cosx}[/tex]

thanks in advance:smile:

Homework Equations





The Attempt at a Solution



i tried substitution of 1 with
cos^2(x)+sin^2(x) and
cosec^2(x)-cot^2(x) and
sec^2(x)-tan^2(x)

but I am stucked agn..
 
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Start by inverting your expression for k to get: [tex]\frac{1}{k}=\frac{\cos x}{1+\sin x}[/tex] ...then multiply both your numerator and denominator by [itex](1- \sin x)[/itex] and simplify...what do you get?
 
oh..yah.. thanks loads. i will get the answer!
 

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