Proving Boundedness of Entire Functions with Harmonic Components

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SUMMARY

The discussion focuses on proving that the product of two harmonic components, \( uv \), is bounded, which is essential for demonstrating that an entire function \( f = u + iv \) is constant. The participants confirm that both \( u \) and \( v \) are harmonic functions, and the proof hinges on the application of Liouville's Theorem. The challenge arises from the assumption that \( u \) and \( v \) are bounded, which is necessary to conclude that \( f \) is constant when \( uv \geq 0 \) everywhere.

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  • Understanding of harmonic functions
  • Familiarity with entire functions
  • Knowledge of Liouville's Theorem
  • Basic concepts of complex analysis
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physicsjock
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Hey,

I'm trying to prove that uv=>0 is bounded so I can state that an entire function is constant when f = u + iv, when f is entire.

I have worked out the rest but I'm struggling to prove that its bounded,

Can you say u=>0, v=>0 then u + v => 0, and that bounded from below?
 
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physicsjock said:
Hey,

I'm trying to prove that uv=>0 is bounded so I can state that an entire function is constant when f = u + iv, when f is entire.

I'm not sure what you are trying to prove - is it given that u,v are harmonic & uv>=0 ?
 
They gave

f = u + iv is an entire function,

that means u and v are harmonic right?

and it asks to show f is constant if uv=>0 everywhere

I think i have done that part just using louivilles theorem, but i realized i was just assuming u and v were bounded
 

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