Proving (csc x + cot x)/(tan x + sin x)=cot x*csc x with SOHCAHTOA

  • Thread starter Thread starter wes28
  • Start date Start date
  • Tags Tags
    Sin
AI Thread Summary
To prove the equation (csc x + cot x) / (tan x + sin x) = cot x * csc x using SOHCAHTOA, start by expressing all trigonometric functions in terms of sine and cosine. Simplify both sides of the equation separately after substitution. The identity sin^2(x) + cos^2(x) = 1 may also be necessary for further simplification. This approach will help clarify the relationship between the two sides of the equation. Ultimately, the goal is to demonstrate that both sides are equivalent through algebraic manipulation.
wes28
Messages
1
Reaction score
0

Homework Statement


I am supposed to show that this statement holds true

(csc x + cot x) / (tan x + sin x) = cot x * csc x
using sohcahtoa

Homework Equations





The Attempt at a Solution



I have tried this

(( h/o ) + (a/o ) / ( o/a + o/h)) 1st

(( ah / o sqrd )) + ((ah / o sqrd )) 2nd

(ah + ah) / (o sqrd) 3rd

after this I cannot see where to go, to show that it
equals cot x * csc x
 
Physics news on Phys.org
do u know how to express all the trigonometric functions in terms of sin and cos??

If you do, then replace each trig func, with its corresponding sin and cos representation, and simplify both sides separately

Thats one of the ways t do it.

PS - U may also need to use a very important identity concerning sines and cosines

1. sin^2(x) + cos^2(x) = 1

Can you prove the above identity? (note: that can be done in the method you have already applied to tackle the problem initially)
 
do u know how to express all the trigonometric functions in terms of sin and cos??

If you do, then replace each trig func, with its corresponding sin and cos representation, and simplify both sides separately

Thats one of the ways t do it.

PS - U may also need to use a very important identity concerning sines and cosines

1. sin^2(x) + cos^2(x) = 1

Can you prove the above identity? (note: that can be done in the method you have already applied to tackle the problem initially)
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top