Proving d(A^-1)/dL = -(A^-1)(dA/dL)(A^-1)

Click For Summary
SUMMARY

The discussion centers on proving the derivative of the inverse of a matrix, specifically the equation d(A^-1)/dL = -(A^-1)(dA/dL)(A^-1). Participants explore the relationship between scalar functions and matrix derivatives, using the analogy of a function of numbers to derive the matrix form. The key approach involves defining B(x) as the inverse of A(x) and applying the product rule to the identity matrix. This leads to the conclusion that the derivative of the inverse matrix can be expressed in terms of the original matrix and its derivative.

PREREQUISITES
  • Understanding of matrix calculus, specifically derivatives of matrix functions.
  • Familiarity with the properties of matrix inverses.
  • Knowledge of the product rule in calculus.
  • Basic concepts of linear algebra, including identity matrices.
NEXT STEPS
  • Study the derivation of the product rule for matrices.
  • Learn about the implications of matrix inversion in linear transformations.
  • Explore applications of matrix derivatives in optimization problems.
  • Investigate the relationship between scalar and matrix derivatives in advanced calculus.
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra and matrix calculus, as well as anyone involved in theoretical physics or engineering applications requiring matrix differentiation.

chill_factor
Messages
898
Reaction score
5

Homework Statement



L = lambda.

Prove: d(A^-1)/dL = -(A^-1)(dA/dL)(A^-1)

Homework Equations



?

The Attempt at a Solution



I did this as an analogy with function of numbers, but don't know how to extend this to matricies. for example:

lets say A = f(L)

d(f(L)^-1)/dL = - (f(L)^-2*d(f(L))/dL = -(A^-1)*dA/dL*(A^-1)

But what is the matrix form?
 
Physics news on Phys.org
chill_factor said:

Homework Statement



L = lambda.

Prove: d(A^-1)/dL = -(A^-1)(dA/dL)(A^-1)

Homework Equations



?

The Attempt at a Solution



I did this as an analogy with function of numbers, but don't know how to extend this to matricies. for example:

lets say A = f(L)

d(f(L)^-1)/dL = - (f(L)^-2*d(f(L))/dL = -(A^-1)*dA/dL*(A^-1)

But what is the matrix form?

I'll use x instead of L, and let B(x) = Inv(A(x)); thus, A(x)*B(x) = I (identity matrix). Take the derivative.

RGV
 
Ray Vickson said:
I'll use x instead of L, and let B(x) = Inv(A(x)); thus, A(x)*B(x) = I (identity matrix). Take the derivative.

RGV

Thanks greatly.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
2
Views
2K
  • · Replies 25 ·
Replies
25
Views
4K
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K