Proving Function Continuity in [-1,30]: Understanding the Example

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Homework Help Overview

The discussion revolves around understanding the concept of function continuity, particularly in the context of proving continuity over specific intervals. The original poster references a textbook example related to continuity in the interval [-1,1] and attempts to apply similar reasoning to their own function defined as f(x)=1-(1/(x-4)), questioning its continuity in the interval [-1,30].

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of continuity and the implications of limits, particularly questioning how to apply these concepts to specific intervals. There is a focus on understanding the prescribed domain and the behavior of functions at points of discontinuity.

Discussion Status

The discussion has evolved with participants clarifying their understanding of continuity and the relevance of the intervals in question. Some have acknowledged the importance of the function's domain while others are still grappling with how to apply the continuity definition to their examples.

Contextual Notes

There is mention of specific intervals and the necessity of considering the function's defined domain, particularly in relation to the continuity of square root functions and the implications of undefined points.

Checkfate
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I am trying to fully understand this example from a textbook I am reading:

http://img59.imageshack.us/img59/9237/continuityyn8.jpg

What I am not understanding is how they are proving it for [-1,1].. The way I see it is they proved that the function is continuous for all values in it's domain...

For example, I thought up this problem on my own to help me understand :

Given f(x)=1-\frac{1}{x-4}, prove that f(x) is continuous in the interval [-1,30] (Obviously it's not continuous at x=4.) The problem is that I don't see the connection between the interval and the solution...

I can just go ahead and prove that \lim_{x\rightarrow a}f(x)=f(a)... Which was stated in my text as meaning that the function is continuous... which it obviously isnt.

\lim_{x\rightarrow a}f(x)=\lim_{x\rightarrow a}(1-\frac{1}{x-4})
=1-\lim_{x\rightarrow a}\frac{1}{x-4}
=1-\frac{1}{a-4}
=f(a)

Can someone cure my confusion? Thanks guys.
 
Last edited by a moderator:
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I am not sure as to whether or not the latex is really screwed up in my post, I edit it and it looks completely diff from what I see when I refresh the post. Click on the indivual latex box's to see what I meant to type if it comes up screwy. Maybe it's just my pc.

Nevermind, it's fine now.
 
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oh my.. I see it now, limf(x)=f(a) for all values except a=4... since that would result in an undefined statement. But I still don't understand how they are testing for the interval [-1,1]... How would I test my made up example in the interval [-1,1]?
 
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They are, indeed, showing it for the values in the function's PRESCRIBED DOMAIN, that is the interval from -1 to 1
 
The only time they implicity use the assmption that x was in [-1,1] was in moving the limit inside the square root. sqrt(x) is only continuous for x>=0, (namely because it is only defined here), so they needed that fact that 1-x^2 was non-negative.
 
Okay I understand what they were doing now, thanks :)

edit:Nevermind this other question, I reread the definition/example and it became clear.
 
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