Proving Gauss's Law with Coulomb's Law: Challenges and Solutions

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Proving Gauss's Law using Coulomb's Law involves integrating the electric field generated by a charge density in three-dimensional space. The integral exists and its divergence is zero outside the charge distribution, allowing the use of the Divergence Theorem for surfaces outside the charge domain. However, challenges arise when the Gauss's surface intersects the charge distribution, particularly regarding the convergence of the electric field integral and the application of the divergence operator. The discussion highlights the complexity of these mathematical concepts, especially for those unfamiliar with the Dirac delta function. Understanding these foundational ideas is crucial for simplifying future calculations in physics.
sadraj
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Hi guys. My question is related to proving Gauss's law by using Columb's law. Let start with a charge density \rho(\vec{r}) in R^3 . by Columb's law we have :
E(\vec{r})=\int{\frac{\rho(\vec{r&#039;})d^3r&#039;(\vec{r&#039;}-\vec{r})}<br /> {|\vec{r&#039;}-\vec{r}|^3}}

suppose that domain of function \rho(\vec{r}) is finite in R^3. Clearly it can be showed that above integral exists for any \vec{r} out of the domain. & it's divergence is zero out of the domain. So for any Gauss's surface out of domain we can use Divergence theoreom to prove that
\int{E(\vec{r}).\vec{dS}}=\int{\rho(\vec{r})d^3\vec{r}}=\frac{Q}{\epsilon 0}

But for a Gauss's surface that goes through domain of \rho(\vec{r}) we have two problems :
1. it is not clear that for all \vec{r} the integral of electric field exist and converges.
2. Suppose that E converges for any \vec{r}. But it is not easy to bring devergence operator in the integral. Divergence theoreom doesn't work here.

What is your idea? Please don't use delta dirac function. I don't understand it. Because I haven't studied distributions in mathematics.
Similar question can be asked when we have surface charge density on the Gauss's surface.
Sorry for bad english
 
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I think its more important that you understand the dirac delta function right now than prove gauss's law. This is a fundamental idea which can greatly simplify many of your future calculations.
 
I believe most of physicists or at least undergraduate people in physics don't understand delta dirac function (Like many things in mathematics) , They just use it. Like me !

I think similar to proving Gauss's law , clearly with divergence theorem out of charge's distribution , there is a way to show Gauss's law is true in other conditions that I interpreted.
 
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