Proving Inequality: Can Partial Derivatives Help?

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Hello!
Say we have an inequality that says that ##f(x, y)>c## where ##f(x, y)## is a function of two variables and ##c## is a constant. Assume that we know this inequality to be true when ##x=a## and ##y=b##. If you show that the partial derivatives of ##f(x, y)## with respect to ##x## and ##y## are both greater than zero, does that prove that ##f(x, y)>c## whenever ##x## is greater than or equal to ##a## and ##y## is greater than or equal to ##b##?
 
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The partial derivatives are positive in the regions ##x>a## and ##y>b##. They could be positive everywhere, but the above is what I think is important to proving that inequality. I could be wrong, though.
 
The mexican hat potential is a counterexample. Only that the derivatives in (0,0) are zero. But then one could define a pole there.
All derivatives are positive, the function values let's say in a circle of radius r are all above c but not outside of it, i.e. for x,y > r.
 
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I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.

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