Proving on the completeness theorem of real number

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The discussion focuses on proving the completeness theorem of real numbers, specifically addressing continuity, supremum, and infimum properties of subsets of real numbers. It outlines tasks such as demonstrating the equivalence of supremum and infimum for non-empty subsets, and establishing the completeness axiom through the Least Upper Bound and Greatest Lower Bound properties. Participants express confusion about how to approach these proofs and are encouraged to share their attempts for guidance. The conversation emphasizes the importance of understanding the relationships between these properties in real analysis. Clarity in these concepts is essential for mastering the completeness theorem.
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1. Homework Statement

(1) ** Show that a function f is continuous at a point c if and only
if for every sequence (xn) of points in the domain of f such that
xn ! c we have limn!1 f(xn) = f(c) = f(limn!1 xn).
(2) Let A be a non-empty subset of R. Dene A := fxjx 2 Ag.
Show the following statements.
(a) A has a supremum if and only if A has an inmum, in
which case we have inf(A) = sup A.
(b) A has an inmum if and only if A has a supremum, in
which case we have sup(A) = inf A.
(3) Show that the completeness axiom of real number system (i.e.
the Least Upper Bound Property) is equivalent to the Greatest
Lower Bound Property: Every non-empty set A of real numbers
that has a lower bound has a greatest lower bound.
HINT: Use (2).
(4) * (Monotone Property) Suppose that A B R, where A =6 ;
and B =6 ;. Show the following statements.
(a) If B has a supremum, then A has also a supremum, and
sup A sup B.
(b) If B has an inmum, then A has also an inmum, and
inf A inf B.
(5) ** Let A and B be non-empty subsets of R such that a b for
all a 2 A and b 2 B. Show that A has a supremum and B has
an inmum, and sup A inf B



2. Homework Equations
The completeness axiom




3. The Attempt at a Solution
I am seriously clueless on how to approach... but I still tried something
But my method seems a bit weird...

 
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