Proving R^2 is metrizable in the dictionary order topology

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SUMMARY

The discussion centers on proving that R^2 is metrizable in the dictionary order topology. The proposed metric is defined as d(x, y) = |x2 - y2| for x1 = y1 and max{|xi - yi| for x1 ≠ y1}, which simplifies to d(x,y) = max{|x1 - y1|, |x2 - y2|}. The participants confirm that the topology induced by this metric matches the dictionary order topology, as open balls can be found within basis elements of both topologies. The key concept is demonstrating that each topology is finer than the other.

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radou
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Homework Statement



As the title suggests, I need to show that RxR is metrizable in the dictionary order topology.

As a reminder, for two elements (a, b) and (c, d) of R^2, the dictionary order is defined as (a, b) < (c, d) if a < c, or if a = c and b < d.


The Attempt at a Solution



The typical basis elements for the dictionary order topology (dot from now on) are represented by either "infinite vertical regions" or "vertical intervals".

If we define a metric on R^2 with:

d(x, y) = |x2 - y2| , for x1 = y1 ; max{|xi - yi|, for x1 =/= y1}

where x = (xi) and y = (yi) are points in R^2,

we can prove that the dot equals the topology induced by this metric, for, if B is some basis element in the dot, we can find open balls which are either regions or open intervals contained in this basis element, whatever it looks like. The same vice versa.

I hope this works.
 
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radou said:
If we define a metric on R^2 with:

d(x, y) = |x2 - y2| , for x1 = y1 ; max{|xi - yi|, for x1 =/= y1}

where x = (xi) and y = (yi) are points in R^2,

This is the same as simply
d(x,y)=max\{ |x_1-y_1|,|x_2-y_2| \}

since if x_1=y_1 then in the max you'll definitely be taking the difference between x_2 and y_2.

we can prove that the dot equals the topology induced by this metric, for, if B is some basis element in the dot, we can find open balls which are either regions or open intervals contained in this basis element, whatever it looks like. The same vice versa.

What do you mean by "the dot"?
 
Office_Shredder said:
What do you mean by "the dot"?

The dictionary order topology, as I stated in the first post.

Office_Shredder said:
This is the same as simply
d(x,y)=max\{ |x_1-y_1|,|x_2-y_2| \}

since if x_1=y_1 then in the max you'll definitely be taking the difference between x_2 and y_2.

Yes, I'm aware of that. But in that case, if given a basis element of the dot of type "vertical intercal", for example, the interval <(a, c), (a, d)>, for any x in this interval, how can I find a basis element of the metric topology defined as you proposed above, if the basis elements in this case (open balls) are square regions?

Btw, the concept of proving two topologies are equal is to show each one is finer than the other.
 

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