Proving R is an Equivalence Relation: Steps and Explanation

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1. Let R be a relation on X that satisfies
a) for all a in X, (a,a) is in R
b) for a,b,c in X, if (a,b) and (b,c) in R, then (c,a) in R.
Show that R is an equivalence relation.




2. In order for R to be an equivalence relation, the following must be true:
1) for all a in X, (a,a) is in R
2) for a,b in X, if (a,b) is in R, then (b,a) is also in R
3) for a,b,c in X, if (a,b) and (b,c) is in R, then (a,c) is in R.




3. The first part is given by the definition of an equivalence relation. I'm stuck on proving part b. Help please!
 
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how about considering (a,b) and (b,b) for the second part?
 
lanedance said:
how about considering (a,b) and (b,b) for the second part?

Proof by contradiction, using lanedance's example.

Or consider (b,c) and (c,c).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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