Proving series is convergent/divergent

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SUMMARY

The series ∞ Ʃ 1 / [(n)(n+1)(n+2)]^(1/3) from n=1 is analyzed for convergence using the limit comparison test. The limit lim {1 / [(n)(n+1)(n+2)]^(1/3)} / (1/n) as n approaches infinity is central to the discussion. The application of l'Hopital's Rule is deemed unnecessary and overly complex for this problem. Simplifying the expression is recommended to facilitate the convergence analysis.

PREREQUISITES
  • Understanding of series convergence tests, specifically the limit comparison test.
  • Familiarity with l'Hopital's Rule and its application in calculus.
  • Basic algebraic manipulation skills for simplifying expressions.
  • Knowledge of cube roots and their properties in mathematical analysis.
NEXT STEPS
  • Research the limit comparison test in detail to understand its application in series convergence.
  • Study algebraic techniques for simplifying complex expressions involving cube roots.
  • Explore alternative convergence tests such as the ratio test and root test for series analysis.
  • Practice problems involving series convergence to solidify understanding of the concepts discussed.
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Homework Statement



The problem is proving that the following series is convergent or divergent:


Ʃ 1 / [(n)(n+1)(n+2)]^(1/3)
n=1

Homework Equations



The limit or direct comparison test

The Attempt at a Solution



lim {1 / [(n)(n+1)(n+2)]^(1/3)} / (1/n)
n->∞

I then attempted to simplify this and use l'Hopital's Rule, but the cube root made it too complicated, and I couldn't come to an answer.
 
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abcde149149 said:

Homework Statement



The problem is proving that the following series is convergent or divergent:


Ʃ 1 / [(n)(n+1)(n+2)]^(1/3)
n=1

Homework Equations



The limit or direct comparison test

The Attempt at a Solution



lim {1 / [(n)(n+1)(n+2)]^(1/3)} / (1/n)
n->∞

I then attempted to simplify this and use l'Hopital's Rule, but the cube root made it too complicated, and I couldn't come to an answer.

l'Hopital is serious overkill. (n)(n+2)(n+2)=n^3(1)(1+1/n)(n+2/n). Try simplifying.
 

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